In a previous article we Designed M20 so let’s design M25 in this one. Let’s say we have to design a Reinforced Concrete Cement(RCC) with a slump of 100 using Cement (Specific Gravity 3.14), 20mm Sub Angular Coarse aggregate (Specific Gravity 2.45) and Zone 2 Sand (Specific Gravity 2.50) for a Moderate exposure condition. These are the steps you will take:
STEP 1 : TARGET MEAN STRENGTH
For MODERATE exposure RCC using 20mm coarse aggregate we need to atLeat use M25 Grade of concrete (As per Table 5 of IS 456 2000)
So lets design M25
Target Mean Strength Fckt = Fck + 1.65xS
Fck = 25MPa (for M25)
Standard deviation for M20-M25 = 4.0 (Table 1 IS 10262 2009)
Fckt = Fck + 1.65×4
Target Mean Strength= 25+ 1.65*4.0=31.60
STEP 2 : CALCULATION FOR WATER CONTENT
For 20mm Aggregates MAX Water Content =186.0 (Table 2 10262 2009)
This value is for Slump within the range of 25-50
For Every 25mm increase in slump we will increase
water by 3%
Current Slump is :100 Which is :50 mm above 50mm
Increase Water Content By :6.00%
186.0+(6.00*186.00)/100 =197.16 Kg/m3
STEP 3 : SELECTION OF WATER CEMENT RATIO
For • REINFORCED Concrete and MODERATE exposure
condition MAX W:C=0 50 (As per Table 5 of IS 456 2000)
STEP 4 : CALCULATION OF CEMENT CONTENT
Cement=WaterContent/w:C
Cement Content=197.16/0.50 = 394.32 Kg/m3
(As per Table 5 of IS 456 2000)Minimum Cement Content is 300
Since
394.32>300 OK
STEP 5 : CALCULATION OF RATIO OF AGGREGATES
For 20mm Coarse and Zone 2 Fine,Volume of Coarse to Total Aggregates=0.62(Table 3 10262 2009)
This value is for w:C =0.50 our w:C=0.50 OK
Fine Agg Ratio=1-Coarse Agg Ratio=0.38
DESIGN MIX CALCULATIONS
Vol of Cement= WT OF CEMETN/(SPGR of
CEMENT*1000)=394.32/(3.14*1000)=0.13
Vol of Water=Wt of Water/1000
=197.16/1000
=0 .20
TOTAL AGGREGATE Vol(e) = 1-(Cement+Water)=0.68
Wt of Coarse Aggregate=e*CoarseRatio*SPGR*1000
= 0.68*0.62*2.45*1000=1028.76 Kg/m3
Wt of Fine Aggregate=e*FineRatio*SPGR*1000
=0.68*0.38*2.50*1000=643.40 Kg/m3
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In a future article we are going to design the M30 concrete mix